Help with Precal
3x^4+2x^2-6x+1 all over x-1

Question

Help with Precal
3x^4+2x^2-6x+1 all over x-1

raden · Answer

use the long division or use the horner's diagram

anonymous · Answer

Can you give an example? i get confused with long division.

raden · Answer

it like you dividing 17 by 3 :v

ganeshie8 · Answer

familiar with synthetic division ?

ganeshie8 · Answer

$
\begin{array}{}

1~|&3&0&2&-6&1\
&&&&\
\hline
&&&&\
&3&&&

\end{array}
$

anonymous · Answer

Oh yeah! So it will be 1 x 3 = 3 . then do i do 3x0 or 3x1?

anonymous · Answer

sorry i was away from the computer for a while, Im here now :)

ganeshie8 · Answer

$
\begin{array}{}

1~|&3&0&2&-6&1\
&&3&&\
\hline
&&&&\
&3&&&

\end{array}

$

ganeshie8 · Answer

next, add 3+0
and put it down in the last row

ganeshie8 · Answer

$
\begin{array}{}

1~|&3&0&2&-6&1\
&&3&&\
\hline
&&&&\
&3&3&&

\end{array}

$

anonymous · Answer

Oh crap right! so it will then be 3 3  on bottom row?

anonymous · Answer

lol gotcha. then i do 3 +2?

ganeshie8 · Answer

yes :)

next, multiply 3*1
and put it in next column in middle row :

$
\begin{array}{}

1~|&3&0&2&-6&1\
&&3&3&\
\hline
&&&&\
&3&3&&

\end{array}

$

anonymous · Answer

I tried to type mine like yours using the equation button but I cant figure it out :P

ganeshie8 · Answer

you got it :)

anonymous · Answer

so 3 3 5

anonymous · Answer

3 3 5 -1 0?

ganeshie8 · Answer

$
\begin{array}{}

1~|&3&0&2&-6&1\
&&3&3&~~5&-1\
\hline
&&&&\
&3&3&5&-1&|~0

\end{array}

$

ganeshie8 · Answer

Correct ! so 0 is remainder and do u knw how to figure out quotient ha ?

anonymous · Answer

hang on let me find my notes! lol

ganeshie8 · Answer

okay !
u can figure out quotient from last row

anonymous · Answer

its 0?

ganeshie8 · Answer

last row has below :
$3~~3~~5~~-1~~|0 $

so, the remainder is :  $0$
quotient is : $3x^2 + 3x^2 +5x - 1$

ganeshie8 · Answer

quotient is ur answer btw :)

ganeshie8 · Answer

$\large \frac{3x^4+2x^2-6x+1}{x-1} =  3x^3 + 3x^2 + 5x-1$

anonymous · Answer

Oh my lol. I knew it was simple just getting there I dont want to make a mistake you know?

anonymous · Answer

Can I try the next one and you check it, if you have time?

ganeshie8 · Answer

sure :)

ganeshie8 · Answer

corrected the typo :

quotient is :  $3x^{\color{Red}{3}} + 3x^2 +5x - 1 $

anonymous · Answer

so 3x^3?

anonymous · Answer

5x^4+5x^2+5 all over x^2-x+1

ganeshie8 · Answer

yes,

3x^3 + 3x^2 + 5x - 1

anonymous · Answer

how did you type it all fancy?

ganeshie8 · Answer

its latex :)

ganeshie8 · Answer

copy paste below :

```
$
\color{red}{heyyyyyyyyyy}
$
```

anonymous · Answer

|dw:1396467231980:dw|