What is the solution set for x squared -8x+4-3?
Walk me through how to solve this please? ( :

Question

What is the solution set for  x squared -8x+4>-3?
Walk me through how to solve this please? ( :

anonymous · Answer

so its x^2-8x+>-3?

anonymous · Answer

with a +4 after the 8

anonymous · Answer

sorry bout that so is it wanting to find the x though

anonymous · Answer

a solution set for x. My choices are 71 x is greater than 1 or x is greatr than 7 x <1 or x>7

anonymous · Answer

the first choice makes no sense

anonymous · Answer

neither does some of the math but how would you make x^2-8x+4 greater the a -3

anonymous · Answer

replace the x with a number that fit both the options and if it works there you go ex. 8^2-8(8)+4>3 i replaced it with an 8 which makes it 16-64+4>3 actually that would make it false cause 16-64=-48+4 = -44 so 3 would be greater

anonymous · Answer

thanks for the help but just guessed

anonymous · Answer

it was the second one lol heads up

anonymous · Answer

and btw youre very beautiful

lyrae · Answer

Another approach:
$$x ^{2} - 8x + 4 > -3  \rightarrow x ^{2} - 8x + 7 > 0$$Assume $$x ^{2}−8x+7=0 \rightarrow x _{1} = 1, x _{2} = 7$$
We know the basic shape of a possitive quadratic and the points where this specific quadratic intersects 0.|dw:1396464237896:dw|From this it's quite easy to derive that the quadratic is grater than 0 when x < 1 or x > 7.