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Mathematics 8 Online
OpenStudy (anonymous):

Solve |x + 5| < 9

OpenStudy (freckles):

if a>0 and you have |f(x)|<a then you do -a<f(x)<a if a>0 and you have |f(x)|>a then you do f(x)<-a or f(x)>a

OpenStudy (freckles):

this is a formula for you

OpenStudy (freckles):

your f(x)=x+5

OpenStudy (freckles):

which of formulas will you use above 1st one or 2nd one?

OpenStudy (anonymous):

1st One ?

OpenStudy (jdoe0001):

\(\bf |x + 5| < 9\implies \begin{cases} +(x + 5) < 9\implies x + 5 < 9 \\ \quad \\ \bf -(x + 5) < 9\implies x + 5 > -9 \end{cases}\) recall that in an inequality, when you multiply by a negative value, you have to \(\bf flip\) the inequality sign

OpenStudy (freckles):

right so you solve -9<x+5<9 and you are done

OpenStudy (rock_mit182):

or you can view it like this:\[-9<|x+5|<9\]

OpenStudy (rock_mit182):

i mean without the absolute parentheses: ( and solve two inequalities at once)\[-9<x+5<9\]

OpenStudy (anonymous):

how do i solve it ? Im Lost sorry

OpenStudy (rock_mit182):

you have to solve for x, that means leave x alone. so you have to get rid off everything else that stay with x

OpenStudy (rock_mit182):

|dw:1396467797108:dw|

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