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OpenStudy (freckles):
if a>0
and you have |f(x)|<a then you do -a<f(x)<a
if a>0
and you have |f(x)|>a then you do f(x)<-a or f(x)>a
OpenStudy (freckles):
this is a formula for you
OpenStudy (freckles):
your f(x)=x+5
OpenStudy (freckles):
which of formulas will you use above
1st one or 2nd one?
OpenStudy (anonymous):
1st One ?
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OpenStudy (jdoe0001):
\(\bf |x + 5| < 9\implies
\begin{cases}
+(x + 5) < 9\implies x + 5 < 9
\\ \quad \\
\bf -(x + 5) < 9\implies x + 5 > -9
\end{cases}\)
recall that in an inequality, when you multiply by a negative value, you have to \(\bf flip\) the inequality sign
OpenStudy (freckles):
right so you solve -9<x+5<9 and you are done
OpenStudy (rock_mit182):
or you can view it like this:\[-9<|x+5|<9\]
OpenStudy (rock_mit182):
i mean without the absolute parentheses: ( and solve two inequalities at once)\[-9<x+5<9\]
OpenStudy (anonymous):
how do i solve it ? Im Lost sorry
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OpenStudy (rock_mit182):
you have to solve for x, that means leave x alone. so you have to get rid off everything else that stay with x