Question

Solve the following inequality.
1/3x^3/4(x − 4)^−2/3 + 3/4x^−1/4(x − 4)^1/3 < 0

Answer 1

I might have wrote it alittle confusing let me try to clear it up

Answer 2

Thanks c:<

Answer 3

\[\frac{ 1 }{ 3 }x ^{3/4}(x-4)^{-2/3}+\frac{ 3 }{ 4 }x ^{-1/4}(x-4)^{1/3}<0\]

Answer 4

@ikram002p

Answer 5

\(\large \frac{ 1 }{ 3 }x ^{3/4}(x-4)^{-2/3}+\frac{ 3 }{ 4 }x ^{-1/4}(x-4)^{1/3}<0\)
\(\large \frac{ 1 }{ 3 }x ^{3/4}(x-4)^{-2/3}<-\frac{ 3 }{ 4 }x ^{-1/4}(x-4)^{1/3}\)
\(\large \frac{ 1 }{ 3 }(x ^{\frac{-9}{8}}(x-4)^{\frac{-2}{3}})<-\frac{ 3 }{ 4 }(x ^{\frac{3}{4}}(x-4)^{\frac{1}{3}} )\)

Answer 6

sry last step i made a typo

Answer 7

\(\large \frac{ 1 }{ 3 }(x ^{\frac{-9}{8}}(x-4))^{\frac{-2}{3}}<-\frac{ 3 }{ 4 }(x ^{\frac{3}{4}}(x-4))^{\frac{1}{3}} \)

Answer 8

\(\bf \large \cfrac{1}{3}x^{\frac{3}{4}}\cdot (x-4)^{-\frac{2}{3}}+\cfrac{3}{4}x^{-\frac{1}{4}}\cdot (x-4)^{\frac{1}{3}} < 0 \quad ?\)

Answer 9

\(\large(x ^{\frac{-9}{8}}(x-4)^{\frac{-2}{3}})<-\frac{ 9 }{ 4 }(x ^{\frac{3}{4}}(x-4)^{\frac{1}{3}} )\) raise both side to power 3
\(\large (x ^{\frac{-9}{8}}(x-4)^{\Huge{-}2})<-\frac{ 27 }{ 64 }(x ^{\frac{3}{4}}(x-4)^{1} )\)

Answer 10

lol are u getting this ?

Answer 11

@jdoe0001 it can be solved :D

Answer 12

okay so i figured out how to do it and that is not correct. you have to leave everything to the right of the less than sign and leave zero by itself. then put the negative numbers under the denominator and find a common factor. thank you for trying though!

Answer 13

negative exponents* i should say