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integral question! integral e^x sinx dx
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\[\int\limits_{}^{}e ^{x}\sin(x)dx\]
Integrate by parts. \[\int e^x\sin x~dx=uv-\int v~du\] where you let \[\begin{matrix}u=e^x&&&dv=\sin x~dx\\ du=e^x~dx&&&v=-\cos x\end{matrix}\] \[\int e^x\sin x~dx=-e^x\cos x+\int e^x\cos x~dx\] Integrate by parts again, this time letting \[\begin{matrix}u=e^x&&&dv=\cos x~dx\\ du=e^x~dx&&&v=\sin x\end{matrix}\] \[\int e^x\sin x~dx=-e^x\cos x+\left[e^x\sin x-\int e^x\sin x~dx\right]\\ 2\int e^x\sin x~dx=e^x(\sin x-\cos x)\\ \int e^x\sin x~dx=\frac{e^x(\sin x-\cos x)}{2}\]
ahh it's that last bit i didn't get! setting it equal to the original equation! i was like... man this is gonna go on forever!!
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