Factor each polynomial:
6n^4-6

Question

Factor each polynomial:
6n^4-6

anonymous · Answer

and show work plz

the_fizicx99 · Answer

is that $\ 6n^4 - 6$ ? or $\ 6n^{4-6}$ ?

anonymous · Answer

the first option

the_fizicx99 · Answer

Yeah, find a gcf and divide it out, 

there's no variable gcf, but there is a coefficient gcf (6). 

$\ 6(n^4 - 1) $

Now factor the differences of squares, assuming you  know what they are,

$\ 6((n^2 + 1)(n - 1)(n+1)) $

anonymous · Answer

thanks:3

the_fizicx99 · Answer

Yw ;D

the_fizicx99 · Answer

It seems a bit tricky in the middle, do you know how we got to n^2 +1 ?

anonymous · Answer

i think when you divide to find the gcf, you divided the exponent in half...........right?

the_fizicx99 · Answer

Erm no you can't divide n^4 by 6,

differences of $\ square $, square root n^4 = n^2 and square-root of 1 is 1 (because 1* 1 = 1)

Now (n^4 -1) = (n^2 + 1)(n^2 -1) = (n + 1)(n-1)

6((n^2-1)(n+1)(n-1))

anonymous · Answer

oh so like a perfect square, just for exponents?

the_fizicx99 · Answer

There's a name for them, there's the perfect squares and differences of squares

the_fizicx99 · Answer

They're called special products :P

anonymous · Answer

oh!

the_fizicx99 · Answer

;P

anonymous · Answer

is it okay is i ask another question?

the_fizicx99 · Answer

I have to get off :< it's already 9:30 and I still need to finish my assignment >.>

anonymous · Answer

oh sorry, then go, thanks for ur help and gn:3

the_fizicx99 · Answer

I'll be on later if you still need help :> bai!

anonymous · Answer

baibai!!