Ask your own question, for FREE!
Chemistry 21 Online
OpenStudy (anonymous):

write a balanced chemical equation for the reaction of lithium and hydronitric acid

OpenStudy (anonymous):

|dw:1396490914602:dw|

OpenStudy (anonymous):

What you have to do is take the cation which is your Li and combine it with your anion which is N and you will get Li3N and then you take your remaining cation, which has an accompanying 2 so it is H2. So your reactant is Li+HN3 and your product is Li3N+H2. Then all you have to do is figure out the coefficients which would go in front and balance the equation.

OpenStudy (anonymous):

We first have to figure out which one to start with. I just went with the H2 on the right side. Since It is H2 we need the H in HN3 to also have 2 so all you do is put a 2 in front of the H and then it will be come 2HN3. So your H is now balanced. But the 2 multiplies with the 3 and your N becomes a 6, so on your product side you need to put a 6 In front of your Li3N. This will come out to be 6Li3N. Now your N is balanced but the 6 multiplies with your 3 in Li3 and it becomes and 18. So on your reactants side it will be 18Li

OpenStudy (anonymous):

Your final answer should look like the drawing i made above. The explanation is very lengthy but the process of doing it doesn't take very long, though it can get confusing.

OpenStudy (anonymous):

Just make sure to check if the multiplication i did was correct

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!