write a balanced chemical equation for the reaction of lithium and hydronitric acid
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What you have to do is take the cation which is your Li and combine it with your anion which is N and you will get Li3N and then you take your remaining cation, which has an accompanying 2 so it is H2. So your reactant is Li+HN3 and your product is Li3N+H2. Then all you have to do is figure out the coefficients which would go in front and balance the equation.
We first have to figure out which one to start with. I just went with the H2 on the right side. Since It is H2 we need the H in HN3 to also have 2 so all you do is put a 2 in front of the H and then it will be come 2HN3. So your H is now balanced. But the 2 multiplies with the 3 and your N becomes a 6, so on your product side you need to put a 6 In front of your Li3N. This will come out to be 6Li3N. Now your N is balanced but the 6 multiplies with your 3 in Li3 and it becomes and 18. So on your reactants side it will be 18Li
Your final answer should look like the drawing i made above. The explanation is very lengthy but the process of doing it doesn't take very long, though it can get confusing.
Just make sure to check if the multiplication i did was correct
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