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What is the pH of a buffer solution prepared by adding 50.00 mL of a 0.20 M solution of NH4Cl (aq) to 50.00 mL of an 0.30 M NH3(aq) solution? (Kb (NH3) = 1.8 x 10-5) a) 9.0 b) 9.1 c) 9.2 d) 9.4 e) more information is needed
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here what is did using henderson hasselbalch: ph= -log(5.5e-10) + log (.3/.2)
found the ka using kw/kb
i got 9.4, is that the right way?
yeah, its right. good job
thanks!
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