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Write the first trig function in terms of the second. sinx;cosx I don't understand the steps to get a final answer.
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hint: \[\Large \sin^2(x) + \cos^2(x) = 1\]
do you see how to isolate sin(x)?
Do I subtract cos?
good first step, then what
doing that will give you \[\Large \sin^2(x) + \cos^2(x) = 1\] \[\Large \sin^2(x) = 1 - \cos^2(x)\] what do we need to do next to isolate sin(x)?
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square root both sides?
very good
\[\Large \sin^2(x) + \cos^2(x) = 1\] \[\Large \sin^2(x) = 1 - \cos^2(x)\] \[\Large \sin(x) = \sqrt{1 - \cos^2(x)}\]
so that would be the final answer?
yes it would
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