Question

alternating series

Answer 1

the error can be no larger than the last term of the partial sum in an alternating sum
find the term that is smaller than \(.01\) and compute the partial sum up to that point

Answer 2

i think you only have to add up the first 4 terms the fifth one \(\frac{1}{5!}=.008...\)

Answer 3

oh wait, that is the third term!
maybe you only have to add the first two

Answer 4

Im still don't fully understand. :/ how would you go through this problem :S

Answer 5

i would find the term that is smaller than \(.01\)

Answer 6

add up until that term

Answer 7

but why did you choose 0.1?

Answer 8

i chose \(.01\) because it said two decimal place accuracty

Answer 9

only first two need to be correct
you can compute only
\[1-\frac{1}{3!}+\frac{1}{5!}\] and you will get it since \(\frac{1}{5!}\) is already small, it is \(.0083333...\)

Answer 10

answer mane1 question

Answer 11

hm actually @satellite73 i think i somewhat understand. ok but how would you approach this one...

Answer 12

#39