Question

PLEASE HELP
Complete and balance an equation for each reaction
Ag + HCINow, I have the solution that the teacher provided us, in order to study for the exam; however, I cannot for the life of me seem to make sense of it.

The solution is 2Ag + 2HCI ->2AgCl + H2

The part I am deeply confused on is: the actual solving part, I can balance the equations perfectly just explain to me step by the step the first part.

And, if possible the same for-

C2H2 + O2
The solution is: 2C2H2+5O2->4CO2+2H2O

Answer 1

so do you?

Answer 2

Ag Is a Nobel metal. It does not
Reduce Hydrogen in hydrochloride acid.

Answer 3

While Nobel prizes medallions are made out of gold, gold is not a Nobel metal :-) It is a noble medal, along with ruthenium, rhodium, palladium, silver, osmium, iridium and platinum.

@meowxx I'm not sure I understand what you are asking. Is the question you have "how do I figure out that Ag and HCl react to make AgCl and H?" or is it something else?

Answer 4

@mathslover sorry, but could you please help me on these two questions real quick before I leave I understood the explanation yesterday for the other, but now these are slightly different and I don't really understand how to apply it.

Answer 5

What you are asking for, I am confused! Can you tell me in which part do you need help ? ( as @wphalmer4 stated earlier)

Answer 6

it's just like yesterday, I have the solutions but I don't understand how to attain them. I don't know how to add Ag and HCI. I can handle the balancing part which comes after though and the same for the second one.

Answer 7

You need to have a look on reactivity series. Ag is more reactive than Hydrogen and hence, Ag replaces H from HCl so H comes out and Ag comes in :

Ag + HCl -> First step : (Ag + Cl) + H

AS you can see H came out and Ag came in and reacted with Cl.

Now, Ag has a valency of +2 and Cl has a valency of -1

Answer 8

You can understand that as :

Ag will release 2 electrons to react with any element but Chlorine only has the tendency to gain 1 electron.

So, Ag will have to react with 2 Chlorine electrons.

So, it becomes \(\sf{AgCl_2}\) + \(\sf H_2\)

Now you can balance it

Answer 9

how do we know Ag has two electrons though?

Answer 10

Just imagine like a dart game where there are many circles. Suppose Ag is similar like that

But the terminology is different.. We call those circles as shells.

In Ag, the outermost shell has only 2 electrons. And in order to gain stability , it has to lose 2 electrons and so, we get to know that Ag has valency of 2+

(It doesn't mean that Ag has only 2 electrons..)

Answer 11

so we only use the one that symbolizes the outer shell, because on my periodic table I see that it has 2, 8, 18, 18, and 1. So, how do I know I use the 2

Answer 12

Okay my fault, Sorry Ag has valency of +1 .. Pardon me, I was just mad at that time to write "+2"..

Answer 13

Notice that Ag has electronic configuration of 2,8,18,18,1 - That is it has 1 electron in the outermost shell. Hence it will be AgCl ( Not AgCl2)

Pardon me again

Answer 14

so it will always be the outermost shell. okay, and also why do we give the electron to Cl and not H? And, can you please do the second one after you answer this question I'm sorry I'm just a bit in a rush right now this exam is super important.

Answer 15

I will try my best, I have to go after 5 minutes. I will try to help in those 5 minutes

Answer 16

We gave the electron from Ag to Cl because H is replaced by Ag and when Ag releases electron then Cl accepts it.

Answer 17

You need to revise the concepts through your books and course. It will be easy for you then.