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Mathematics 53 Online
OpenStudy (anonymous):

WHAT IS THE PRINCIPAL SQUARE ROOT OF i??????

OpenStudy (abbles):

The square root of i equals: (square root of)2/2(1 + i)

OpenStudy (anonymous):

Would that become 0.71+i?

OpenStudy (abbles):

\[\sqrt{2}/2*(1 + i)\]

OpenStudy (anonymous):

or 0.71+0.71i ??

OpenStudy (abbles):

That is the simplified version. Here, this explains it well. Look under "square roots" .. http://en.wikipedia.org/wiki/Imaginary_unit

OpenStudy (anonymous):

Okay. :) I just need to know the simplified version of it and i'm not quite sure how to get it there. I have the options of 0.71+i, 0.71+0.71i, 3.14+0.71i, 1.414+i. i know that the square root of 2 divided by 2 is 0.71. So would it be 0.71 + i ???

OpenStudy (abbles):

Simplified it would be 0.707106781 + 0.707106781 i, but you could round it to 0.71 + 0.71i. You can get this by simplifying the answer I put earlier, and plugging it into Google calculator works, too.

OpenStudy (anonymous):

Oh! Wow, thank you soooo much!! @Abbles

OpenStudy (abbles):

no problem :)

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