Question

What would the electron configurations of each of the following when they are A) atoms, and B) ions, and C) what would the charge be?:
- Sodium

Answer 1

your question is confusing

Answer 2

is sodium your answer ?

Answer 3

no, it is one of the elements that I have to find the electronic config for when it is a atom, ion and charge

Answer 4

and finding the charge

Answer 5

ohhhhhhhhhh ok

Answer 6

Any idea how this works?

Answer 7

yes

Answer 8

is the electronic configuration 2,8,2?

Answer 9

but when you have to make the shells equal, how do you do it?

Answer 10

could this question now be tried with fluorine ?

Answer 11

Is it like the 1s2 2s2 2p6 3s2? Sorry if I don't help. ^_^ Hehehe! Let's see how you get the answer.

Answer 12

@petiteme Sodium is in the first group of the 3s period.
so it would be \(\Large\sf 1s^2\ 2s^2\ 2p^6\ 3s^1\) or \(\Large\sf [Ne]3s^1\)

Answer 13

I agree. ^_^ Hehe well I haven't checked though. Just asking if he knows it ^_^ Good job though :D

Answer 14

now for the ion \(\sf (Na^+)\), it donates 1 electron. So the configuration becomes
\(\Large\sf 1s^2\ 2s^2\ 2p^6\)

Answer 15

sodium normally has 11 electrons. That would be 2 electrons in the first shell, 8 in the second and 1 in the third

Answer 16

when it ionizes, it loses 1 electron, so it would become 2,8,0

Answer 17

@TL9800