Express the series below in summation notation for the specified number of terms.
\[\sum_{n=0}^{10} An\]
6. 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9
would the sigma be correct for the series
Remember, your ending point is 10. Also what happened to A?
i dont know
it increases by 1
Well, in the original problem it was being multiplied by your variable n. Because it's a common factor, you can factor it out after you write out the series.
how would the sigma look like then
\[\sum_{n=0}^{10}An= An_0 + An_1 + An_2 ... + An_n=A(n_0+n_1+n_2...+n_n)\] Or in this case, another way to look at it is: \[ \sum_{n=0}^{10}An=A \sum_{n=0}^{10}n \]
That's a slightly generalized expression. It would probably be better to generalize it like: \[ \sum_{n=0}^{i}An =A \sum_{n=0}^{i}n =An_0+An_1+An_2+....+An_i=A(n_0+n_1+n_2+....+n_i)\]
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