15.00 mL of 1.600 M NaOH solution exactly neutralizes 20.00 mL of an unknown monoprotic acid solution. Calculate the molarity of the acid solution
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First write out the reaction equation I will do it for you because it is easy XH + NaOH -> H2O + NaX This tells you that for every 1 mole of the monoprotic acid 1 mole of NaOH is consumed Molarity Formula **MEMORIZE** Molarity = Moles/Liters you need to find moles of NaOH reacted with the acid, this will tell you the number of moles of monoprotic acid you have! Remember the reaction is 1 to 1 (meaning that for everyone part acid consumed one part base is consumed) From there you can apply the the Molarity formula to find the concentration of monoprotic acid because you know its volume and moles
Just to help clarify the concept if it was a diprotic acid used the formula would be H2X+ 2NaOH = 2H2O + Na2X Ignore the Na2X it doesnt really matter in this example Thus you would have a 2 to 1 ratio, for every 1 mole of acid used it will react with 2 moles of base Therefore you would have to find the moles of base and divide it by 2 to find the moles of acid Hope this helps
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