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\[\sum_{k=1}^{\infty}=\frac{ 1 }{ k }-\frac{ 1 }{ k+2 }\]
Ummmmmmm. Im not that smart
so this is a telescoping series, just do a few partial sums and you'll see what the series equals
didn't get that(
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(1-1/3)+(1/2-1/4)+(1/3-1/5)+(1/4-1/6)... some of the terms got cancelled out
so the result should just be (1+1/2) or something similar to that
thx :D
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