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Mathematics 19 Online
OpenStudy (anonymous):

Help!

OpenStudy (anonymous):

What you need help with

OpenStudy (anonymous):

\[\sum_{k=1}^{\infty}=\frac{ 1 }{ k }-\frac{ 1 }{ k+2 }\]

OpenStudy (anonymous):

Ummmmmmm. Im not that smart

OpenStudy (anonymous):

so this is a telescoping series, just do a few partial sums and you'll see what the series equals

OpenStudy (anonymous):

didn't get that(

OpenStudy (anonymous):

(1-1/3)+(1/2-1/4)+(1/3-1/5)+(1/4-1/6)... some of the terms got cancelled out

OpenStudy (anonymous):

so the result should just be (1+1/2) or something similar to that

OpenStudy (anonymous):

thx :D

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