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Mathematics 7 Online
OpenStudy (anonymous):

Write the expression -3x 2 + 2y 2 + 5xy - 2y + 5x 2 - 3y 2 in simplest form. Then, answer the following questions using complete sentences.

OpenStudy (phi):

do you see any "like terms" that you can combine ?

OpenStudy (anonymous):

no I dont understand it

OpenStudy (phi):

your equation is this (btw, you should use ^ to show exponents) -3x ^2 + 2y ^2 + 5xy - 2y + 5x^ 2 - 3y^ 2 if we use the equation editor (see button on the lower left) \[ -3x ^2 + 2y ^2 + 5xy - 2y + 5x^ 2 - 3y^ 2 \] a "like term" is the same variable (letter) to the same exponent. the number in front does not matter. do you see any "like terms" ?

OpenStudy (anonymous):

_3x^2 and 5x^2

OpenStudy (phi):

yes, but that is a minus sign in front of the 3 \[ -3x^2 + 5x^2 \] now we use this idea: you have 5 "x squared"s and take away 3 "x squared"s how many \(x^2\) do you have left ?

OpenStudy (anonymous):

idk

OpenStudy (phi):

how about if you had 5 brooms and took away 3 brooms. How many brooms do you have? or you have 5 apples and take away 3 apples ? or 5 x^2 take away 3 x^2, how many x^2 ?

OpenStudy (anonymous):

2

OpenStudy (phi):

yes. so \[ -3x^2 + 5x^2 = 2 x^2\] you start with 5 of the x-squareds and take away 3 of them. that leaves you with 2 of them

OpenStudy (anonymous):

so thats the answer

OpenStudy (phi):

that is part of the answer. so far, we started with \[ {-3x ^2} + 2y ^2 + 5xy - 2y + 5x^ 2 - 3y^ 2 \] you simplified the x^2 part (combined them) so you now have \[ 2x ^2 + 2y ^2 + 5xy - 2y - 3y^ 2 \] can you find any more "like terms" ? hint: there are more

OpenStudy (anonymous):

2x^2and 2y^2

OpenStudy (phi):

a "like term" is the same variable (letter) to the same exponent. the number in front does not matter.

OpenStudy (anonymous):

ok

OpenStudy (phi):

2x^2and 2y^2 have DIFFERENT letters, so NOT like terms. keep looking

OpenStudy (anonymous):

2y2 and 3y2

OpenStudy (phi):

we have to be careful about the signs. One way to write this is \[ 2x ^2 + {\bf2y ^2} + 5xy - 2y + {\bf- 3y^ 2} \] so the two like terms are \[ 2y^2 \text{ and } -3y^2 \]

OpenStudy (phi):

can you combine them ? (you get a negative number out front)

OpenStudy (anonymous):

what you mean combine them

OpenStudy (phi):

\[ 2y^2 - 3y^2 \] means you have 2 y-squared and take away 3 y-squared

OpenStudy (phi):

do you know how to do 2 - 3 ?

OpenStudy (anonymous):

yea

OpenStudy (phi):

what do you get ?

OpenStudy (anonymous):

-1

OpenStudy (phi):

and that is the clue to what is \[ 2y^2 - 3 y^2 \]

OpenStudy (anonymous):

ok

OpenStudy (phi):

what do you get ?

OpenStudy (phi):

2 y-squared and take away 3 y-squared leaves how many y^2 ?

OpenStudy (anonymous):

1

OpenStudy (phi):

almost. \[ 2y^2 - 3y^2 \text{ is not } 1y^2 \] \[ 3 y^2 - 2 y^2 = 1y^2 \]

OpenStudy (anonymous):

-1y^2

OpenStudy (phi):

you get a *negative number* of y^2

OpenStudy (phi):

yes. now we have \[ 2x ^2 + {\bf2y ^2} + 5xy - 2y + {\bf- 3y^ 2} \] simplifies (by combining the y^2 terms) to \[ 2x ^2 + {\bf-y ^2} + 5xy - 2y \] or \[ 2x ^2-y ^2+ 5xy - 2y \]

OpenStudy (phi):

notice that -1y^2 is usually written as -y^2 (it means the same thing)

OpenStudy (anonymous):

i understand it now the answer is 2x^2-y^2=5xy-2y i think is it right?

OpenStudy (phi):

there is no = sign, unless there was an = sign in the original

OpenStudy (anonymous):

ok

OpenStudy (phi):

I guess you made a typo, and meant +

OpenStudy (phi):

can you do the rest of the problem Then, answer the following questions using complete sentences.

OpenStudy (anonymous):

what to do now

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