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according to the VSEPR theory what accounts for waters bond angle of 104.5
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According to the VSEPR theory, w1hat accounts for waters bond angle of 104.5?
The lone pair repulsions.
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According to the VSEPR theory. lone-lone pair repulsion > bond pair - lone pair repulsion > bond bond pair repulsion. In the $$\huge H_2O $$ molecule the lone pair of electrons on the $$\huge O$$ atom cause the the bond pair to constrict and move away due to the force of repulsion. Thus the angle is decreased to $$\huge 104.5^0$$
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