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OpenStudy (anonymous):

according to the VSEPR theory what accounts for waters bond angle of 104.5

OpenStudy (aravindg):

So what is your question?

OpenStudy (anonymous):

According to the VSEPR theory, w1hat accounts for waters bond angle of 104.5?

OpenStudy (aravindg):

The lone pair repulsions.

OpenStudy (anonymous):

your mom

OpenStudy (anonymous):

OpenStudy (praxer):

According to the VSEPR theory. lone-lone pair repulsion > bond pair - lone pair repulsion > bond bond pair repulsion. In the $$\huge H_2O $$ molecule the lone pair of electrons on the $$\huge O$$ atom cause the the bond pair to constrict and move away due to the force of repulsion. Thus the angle is decreased to $$\huge 104.5^0$$

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