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eq. of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the centre and r is the radius of the circle.
for bigger circle what is the centre?
0 @surjithayer
it is (0,0)
now what is the radius?
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its radius is 6 so eq. is (x-0)^2+(y-0)^2=6^2 or x^2+y^2=36
similarly what is the centre of next circle?
The one on the far right on the x-axis line is (0, 8)
it is (8,0) and radius=?
radius=1
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write the eq.
(x-h)^2+(y-k)^2=r^2 (x-0)^2+(y-0)^2=8^2 Like this? @surjithayer
x^2+y^2=64
(x-8)^2+(y-0)^2=1^2 x^2-16x+64+y^2=1 x^2+y^2-16x+63=0
similarly for third centre is (8,6) and radius=2 write the equation.
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(x-h)^2+(y-k)^2=r^2 (x-8)^2+(y-6)^2=2^2 Like that? @surjithayer
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