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Algebra 19 Online
OpenStudy (anonymous):

Help me please, algebra 1 question.

OpenStudy (anonymous):

Scores on a statewide standardized test are normally distributed with a mean of 12.89 and a standard deviation of 1.95. Certificates are given to students whose scores are in the top 2% of those who took the test. This means that they scored better than 98% of the other test takers. Marcus received his score of 13.7 on the exam and is wondering why he didn’t receive a certificate. Show all work to determine whether Marcus’ score was high enough to earn a certificate. Write a letter to Marcus explaining whether or not he will be receiving a certificate. Include a brief summary of your statistical analysis in your letter.

OpenStudy (anonymous):

Scores on a statewide standardized test are normally distributed with a mean of 12.89 and a standard deviation of 1.95. Certificates are given to students whose scores are in the top 2% of those who took the test. This means that they scored better than 98% of the other test takers. Marcus received his score of 13.7 on the exam Z score = (score - mean)/standard deviation Marcus Z score = (13.7 - 12.89)/1.95 = 0.4154 Z(0.4154) = Pr(0.1735) or 17.35% + 50% = 67.35% ----------- The "cut off" mark for a certificate Pr (0.48) or 48% = Z (2.05) 2.05 = [cut off mark - 12.89]/1.95 3.9975+ 12.89 = 16.8875 = 16.9 rounded

OpenStudy (anonymous):

I'm sorry. whats Pr? And where did you get .48 to find the cut off mark? @valeriemc

OpenStudy (anonymous):

valeriemc has used probabilities to solve it. pr means probability and because the chances are 50% (whether marcus would receive the certificate or not that why the chances of receiving a certificate would be 50%) and we are finding whether he was in the 2% list or not that's why 2% was subtracted from 50% which gave us 48% which is 0.48. hope my explanation clears your thoughts

OpenStudy (anonymous):

I'm still really confused..can someone help clear things up?

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