CAN SOMEONE HELP ME PLEASEI NEED HELP

Question

aaronq · Answer

if you don't post the question no one can help you.

anonymous · Answer

Explain, in terms of particles, concentration, and reaction rate, what you expect to happen when methane gas (CH4) and hydrogen sulfide gas (H2S) are sealed in a flask and reach a state of equilibrium.

CH4 (g) +2 H2S (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. CS2 (g) + 4 H2 (g)

anonymous · Answer

@aaronq

aaronq · Answer

particles of  $CH_4$ and $H_2S$ will collide with one another.

Since the concentration is greatest at first, and the rate is dependent on it, the rate will be fastest at first and slow down as the concentrations of the reactants decrease. This will occur until a point and the rate of the forward reaction will stay constant. 
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At the same time products will react with one another, and since their concentrations are increasing, the rate of the backward reaction will increase, up to a point, where it equals the forward rate.|dw:1396548701597:dw|

At equilibrium the concentrations of both products and reactants are fixed, although the reactions are still occurring.