Question

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!
int_{1}^{8}4x ^{1/3}dx

Answer 1

int_{1}^{8}4x ^{1/3}dx

Answer 2

\[\int\limits_{1}^{8}4x ^{1/3}dx\]

Answer 3

You'll want to use the identity \(\int x^r dx = \frac{1}{r+1}x^{r+1} + C \text{ if } r \neq -1\). In your case, r = 1/3.

Answer 4

Maybe indentity is the wrong word but you get the idea.

Answer 5

\[\int\limits_{a}^{b} k*x ^{r} dx = k \int\limits_{a}^{b}x ^{r}\]
where k is constant
and r is the exponent

Answer 6

onde k é uma consante
e r é o exponente da funcao

Answer 7

certo

Answer 8

sim meu amigo, voce estudia engenheria ?

Answer 9

sim amigo, estou vendo essa matéria agora...

Answer 10

5*3^2
= 45

Answer 11

está certa a resposta?

Answer 12

I'm not allowed to give you a final answer, those are the rules here

Answer 13

amigo, isso é um oito ?

Answer 14

o é uma S ?

Answer 15

found this result, now I wonder if it is correct.

Answer 16

i wonder if the top of the integral is a number or a letter

Answer 17

I mean, cannot see it clear, is an 8 or S ?

Answer 18

is the number 8

Answer 19

\[= \frac{ x ^{\frac{ 1 }{ 3 }+1} }{ 1/3+1 }\] evaluated in 0 and 8 (i guess,ñao olho bem a expressao arriba na integral )

Answer 20

1 and 8 ?

Answer 21

int_{1}^{8}4x ^{1/3}dx

Answer 22

?

Answer 23

\[\int\limits_{0}^{8}4x ^{\frac{ 1 }{ 3 }}dx=4\int\limits_{0}^{8}x ^{\frac{ 1 }{ 3 }}dx=4[\frac{ x ^{\frac{ 1 }{ 3 }+1} }{ \frac{ 1 }{ 3 }+1 }]_{0}^{8}\]

Answer 24

\[4[\frac{ 3\sqrt[3]{8^{4}} }{ 4 }]\]=