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Calculus1 4 Online
OpenStudy (anonymous):

Water is flowing into a spherical tank with 6 foot radius at the constant rate of 30pi cu ft per hour. When the water is h feet deep, the volume of water in the tank is give by V=(pih^2)/3 * (18-h) What is the rate at which the depth of the water in the tank is increasing at the moment when the water is 2 feet deep? Answer: 1.5 ft per hr How do you come to this answer?

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