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Mathematics 19 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

Go by a process of elimination. I think we can safely say it's not 115.3

OpenStudy (anonymous):

Well that idnt help well.

OpenStudy (anonymous):

That line that measures 19 looks like it's longer than a radius.

OpenStudy (anonymous):

im bad at maths

OpenStudy (anonymous):

No you're not, just look at it like a game, try to find a reason to rule answers out.

OpenStudy (jziggy):

Process of elimination won't always be helpful, So look at what you know. If you look at half of the line that measures 19 you can make a triangle whose hypotenuse is equal to the radius.

OpenStudy (nikato):

|dw:1396582324917:dw| so this is whats given

OpenStudy (nikato):

|dw:1396582389509:dw| do you know the length of that? remember that the chord is bisected perpendicular from a line from the center

OpenStudy (anonymous):

I think you're complicating things for nothing.

OpenStudy (nikato):

ok well... theres a theorem that states in a circle, the perpendicular bisector of a chord passes through the center of the circle which means 19/2= 9.5 |dw:1396582757876:dw| and using the pythagoreom theorem, you can find x, which would be the radius so 5^2 + 9.5^2=x^2 solve for x

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