Can someone help me solve for the smaller segment of a circle. chord 3sqr2 and angle is 90 degrees
Do you have a picture ?
and exactly what is the question ?
yes,
is it like this? |dw:1396619085677:dw|
yes that's the picture
and exactly what is the question ?
find the area of the smaller segmebt of the cicle. round your answer to two decimal points
First, you need to find the radius. Notice you have a right angle so you have a right triangle do you know the pythagorean theorem ?
c=asq2 + bsqr2
yes, now to use that formula we have to label the triangle's sides. we can label its legs "r" (for radius) because both legs are a radius. what is c (hypotenuse) in our triangle ?
3sqr2
ok. we should tweak your version of pythagoras it is \[ c^2 = a^2 + b^2 \] to use it , replace c with \(3 \sqrt{2} \) replace a with r replace b with r can you do that ?
ok, i did that and equation is 18=rsqr2+rsqr2
yes if you use the equation editor it looks nicer \[ 18 = r^2 + r^2 \] if you have 1 r squared and add another r squared how many r^2 do we have ?
2
which means \[ 18 = r^2 + r^2 \] simplifies to \[ 18 = 2r^2 \] can you solve for r ? The next step is divide both sides by 2
r=3
The next step is what is the formula for the area of a circle ?
\[pirsq\]
A = pi r^2 (use ^ to show 2 is an exponent) so the area of the whole circle is A= pi * 3^2 = 9 pi
ok thank u
next, the "sector" is what fraction of the circle ?
if the whole circle is a pie, the sector is what fraction of the whole pie ?
can you guess ?
1/4
|dw:1396620671790:dw|
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