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OpenStudy (luigi0210):
Let \(f(x)=x^2e^{-x}\)
Find the inflection points:
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OpenStudy (luigi0210):
So I got the first derivative as \(\large f'(x)=-e^{-x}(x^2-2x)\)
Second I'm not sure..
OpenStudy (luigi0210):
Second I got \(\large f''(x)=e^{-x}(x^2-4x+2)\)
OpenStudy (anonymous):
ye
OpenStudy (luigi0210):
So I pretty much just use quadratic formula for the rest?
OpenStudy (luigi0210):
Since e^-x cant be solved at 0?
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OpenStudy (anonymous):
Yeah, I guess so.
OpenStudy (luigi0210):
We'll see how that work out, thanks xD
OpenStudy (anonymous):
I'm pretty rusty on these things...been a while, since I've done these problems, I always hated them...curve sketching..bleh.
OpenStudy (luigi0210):
You did good batman, now let's ride your unicorn back to base instead of the batmobile ;)
OpenStudy (anonymous):
Woot Woot :D
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OpenStudy (anonymous):
Curve sketching is the last of first semester calc, I think.
OpenStudy (luigi0210):
I got \[\LARGE 2 \pm \sqrt{2}\] but I feel like I'm meissing something..
OpenStudy (anonymous):
WOLFRAM
OpenStudy (luigi0210):
xD
Oh how we're too lazy nowadays >_>
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