Let \(f(x)=x^2e^{-x}\) Find the inflection points:
So I got the first derivative as \(\large f'(x)=-e^{-x}(x^2-2x)\) Second I'm not sure..
Second I got \(\large f''(x)=e^{-x}(x^2-4x+2)\)
ye
So I pretty much just use quadratic formula for the rest?
Since e^-x cant be solved at 0?
Yeah, I guess so.
We'll see how that work out, thanks xD
I'm pretty rusty on these things...been a while, since I've done these problems, I always hated them...curve sketching..bleh.
You did good batman, now let's ride your unicorn back to base instead of the batmobile ;)
Woot Woot :D
Curve sketching is the last of first semester calc, I think.
I got \[\LARGE 2 \pm \sqrt{2}\] but I feel like I'm meissing something..
WOLFRAM
xD Oh how we're too lazy nowadays >_>
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