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Calculus1 16 Online
OpenStudy (anonymous):

If f(x)=e^2x and g(x)=lnx, then the derivative of y=f(g(x)) at x=e is Answer: 2e How do you get to this answer? Please explain.

hartnn (hartnn):

whats f(g(x)) you got ?

hartnn (hartnn):

f(g(x)) is when you put g(x) as x in f(x)

OpenStudy (anonymous):

so i put g(x) into f(x) and got y=2x

hartnn (hartnn):

thats correct! :) what its derivative

OpenStudy (anonymous):

then do i just put e in for x?

hartnn (hartnn):

i think you got y=x^2 then its derivative dy/dx = 2x right ?

hartnn (hartnn):

and yes, then you just put x= e :)

OpenStudy (anonymous):

oh that's so much easier than i thought. thanks again :)

hartnn (hartnn):

welcome ^_^

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