Simplify...
\[(3x)^-1/3\]
@amistre64 @ikram002p
@tnt4ever
Hmm
the power is -1/3 just so you know.
I really have no good clue sorry :(
so (3x) to the -1/3 power.
What grade?
It's algebra 2.
Oh ok im working all up in algebra 1 sorry.
oh okay that's fine. thanks anyways.
i assume its just applying a property of exponents .... what does a negative exponent tell us? what does a fractional exponent tell us?
i got no idea what it means to simplify it tho .... rewrite it in another way maybe? but its pretty simple to me as is
a negative exponent would mean the numerator would be one.
reciprocal, yeah. so this starts to look like a fraction
so in this case I get\[\frac{ 1 }{ \sqrt[3]{3x}}\]
thats a good assessment to me. if its simplified ... i got no idea some may want you to rationalize the denominator and such, but thats just busy work and doesnt really simplify anything in my opinion
the book I use does not like for the denominator to have the root of a number symbol... so in this case, how would I get rid of that cube root of 3x so as to leave the denominator with a digit.
we could have started with just multiplying by 1 \[(3x)^{-1/3}\] \[\frac{1}{(3x)^{1/3}}*\frac{(3x)^{2/3}}{(3x)^{2/3}}\] \[\frac{(3x)^{2/3}}{(3x)^{2/3+1/3}}\] \[\frac{(3x)^{2/3}}{3x}\]
this is confusing :/ ughhh
I don't understand the first step.
:) i flipped, multiplied by a useful form of 1 that would add the exponents to eliminate any radicals
you agree that 1/3 + 2/3 = 1 right?
yes! okay so anything to remove the radical at the bottom... Thanks, I get it now.
good ;)
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