Write an equation in slope-intercept form for the line that passes through (0,6) and is parallel to the line described by y=2x+3.

Question

luigi0210 · Answer

Take the slope from the equation of $m=2$ and the points $(0,6)$ and plug it into $y-y_{1}=m(x-x_{1})$

anonymous · Answer

How do I do that?

anonymous · Answer

@Luigi0210

luigi0210 · Answer

Well you got $m$ and $(x_{1},~y_{1})$, just plug them in and solve.

luigi0210 · Answer

The number on $y_{1}$ is just a subscript not an exponent. And you got it backwards :/

anonymous · Answer

ok..

luigi0210 · Answer

We have the point-slope formula: $\large y-y_{1}=m(x-x_{1})$
And we have the coordinates: $\large (0, 6)==>(x_{1},~y_{1})$
And the slope: $\large m=2$ from $\large y=2x+3~===>~y=mx+b$ where $m=slope$

luigi0210 · Answer

So plugging that in.. $\large y-(6)=2(x-0)$ 
Can you simplify that into $\large y=mx+b$?

anonymous · Answer

Yes. Thanks for the help.

luigi0210 · Answer

No problem, and good luck!