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Solve for d. sqrtd^2-11 = 5 4, -4 5, -5 5, 6 6, -6
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@Hero
The equation is \[\sqrt{d^2}-11=5\] right?
the squareroot goes all the way to 11
oh okay. So, you're solving \[\sqrt{d^2-11}=5\] well, the square root of d^2 is d. So, you can rewrite this as \[d-\sqrt{11}=5\] Following?
The squareroot of 11 is 3.31
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Right. So, what -3.31 gives you 5?
what do you mean what -3.31 gives you 5?
What gives you 5 when you subtract 3.31?
1.69?
Hmm.... doesn't seem to be one of your answers. Can I see the full problem? Maybe I'm not understanding this.
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step by step answer is here http://www.mathskey.com/question2answer/11481/solve-for-d-sqrtd-2-11-5
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