I really need help with a worded answer quiz please help me I need to finish this so I can move on with my other school work (:
mhmm
@apollard99 if u dont get it its fine i dont either
Sorry, im not good with this.
@potato_donuts
the ball in the picture looks like it goes up to a height of about 20 or 21 feet, hard to see exactly
the ball given by the height \[ h=–16t^2 + 48t + 15 \] has a maximum at the second coordinate of the vertex the first coordinate of the vertex is \[-\frac{b}{2a}=\frac{48}{32}=\frac{3}{2}\]
if you put in \(\frac{3}{2}\) for \(t\) you get \(51\) which is larger than 21
i will leave the "complete sentences" up to you, but the answer is what i wrote above
okay thank you! yeah im very good with writing just not the math part :P can u help me with parts 2 and 3?
what are they?
the equation \(h=-16t^2+48t+15\) means at time \(t=0\) you have \(h=15\) i.e. you are 15 feet up seems like a platform to me in the graph when \(t=0\) you are about at 5 feet up so standing on the floor
as for the height of the platform, since the person not standing on the platform throws the ball from a height of 5, and the person on the platform throws from a height of 15 , i would estimate the height of the platform at \(15-5=10\) feet up
site is really slow, hope you got that
yeah im noticing that it took me like 3 minutes to be able to fan you but yes im getting all of this
it is increasing where the curve is going up
in the graph that is from \(t=0\) to \(t=1\)
in the equation from \(t=0\) to \(t=\frac{3}{2}=1.5\)
Thank you (:
as for the rate of change the ball in the graph goes from 5 to 20 one second, so the rate of change is 15 feet per second on average
the one in the equation goes from 15 to 51 in 1.5 seconds, so the rate of change is \(51\div 1.5= 34\) feet per second
oops mistake!!
rate of change is \((51-15)\div 1.5=36\div 1.5=24\) feet per second
gotta run, good luck
thanks for this (:
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