plz help:using the fact that 15=45-30, determine the exact value of sin 15 in simplest radical form
@Hero plz help
sin(a - b) = sin(a)cos(b) - cos(a)sin(b)
is tht formula?
sin(45 - 30) = sin(45)*cos(30) - cos(45)*sin(30)
Yes that is the formula. All you have to do is just plug in the values and then simplify.
what do u do with 15?
Put it this way: sin (15) = sin(45 - 30) = sin(45)*cos(30) - cos(45)*sin(30)
so this is wht I got:
sin15=sin(15)=(raidcal2/2)(radical3/2)-(raidcal2/2)(radical1/2)
Okay, so simplify it further
sin(45 - 30) should stay as 45 - 30
I shuld multiply radical2/2*radical3/2
Yes, you should
i got 1.224744871
Not into decimals though
raidcal6/2?
it tht rit?
Should be \(\dfrac{\sqrt{6}}{4}\) for that part
ye thts what i meant
so i got sin15=sin(15)=radical4/4?
good?
@Hero
Not exactly
You should have ended up with \(\sin(15) = \dfrac{\sqrt{6} - \sqrt{2}}{4}\)
oh thts my final answer? i cnt subtract radical6-radical2? bc the denominators are same
How would you subtract \(\sqrt{6} - \sqrt{2}\)? Remember, you can't subtract if there is no property that allows you to.
You can only do what the properties say that you can do.
If you can find a radical or exponential property that allows you to subtract in that manner, then you can. Otherwise, you can't.
oh got so thts my finasl answer? rit?
@Hero
Yes, that is the final answer
thnks so much ur awesome! i appreciate ur time and help
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