Which of the following constants can be added to x^2 - 6x to form a perfect square trinomial?

A.) 6

B.) 9

C.) 36

Question

Which of the following constants can be added to x^2 - 6x to form a perfect square trinomial?

A.) 6

B.) 9

C.) 36

the_fizicx99 · Answer

I'm going to go out on a limb here and say you're solving for the 3rd term

x^2 - 6x + ___

√x^2 = x


So the coefficient of the middle term 2ab = 2(x)(b) = 2xb.

2xb =    6x
/2x        /2x

b = 3


(x-3)^2 = x^2 -2(x)(3) - 3^2 = x^2 -6x + 9

anonymous · Answer

..?

the_fizicx99 · Answer

What part didn't you get?

anonymous · Answer

Any of it?

the_fizicx99 · Answer

.-.

K, what exactly are you trying to solve for?

anonymous · Answer

I don't know, that's why I posted it on here.

the_fizicx99 · Answer

Hm, well a perfect square trinomial is in the form of (a+b)^2 or (a-b)^2

Understand so far?

anonymous · Answer

No ma'am. I'm new to all this, so I don't get any of it.

the_fizicx99 · Answer

Hmm,

Well a perfect square trinomial is: $\ (a+b)^2 = a^2 + 2(a)(b) + b^2 $ understand?

the_fizicx99 · Answer

And then there's the differences of squares: $\ (a-b)^2 = a^2 -2(a)(b) - b^2 $