More Financial Algebra help! Every six months, Jessa deposits $525 into an interest-bearing account to save for her children’s tuition. The interest rate on the account is 5.4% compounding semiannually. What is the present value of the investment if Jessa’s children leave for college in 11 years? $8,623.98 $6,665.39 $8,856.83 $7.025.32 I keep getting this as my answer: 1669.7549618492145787 which is nowhere close to any of the answer choices given above. ):
This is how I have my problem set up FV = 525(1 + (5.4/100))^(2 * 11)
@ganeshie8 Mind helping me again? lol :p
Would I set it like this? FV = 525/(1 + (5.4/2))^(2 * 11)
Never mind..that didn't work either :l
hint : its not a single deposit
well you need the formula for the future value of an annuity.... an annuity is a situation where the same amount is deposited under the same conditions.... the formula is \[FV = M \times \frac{(1 + r)^n -1}{r}\] M is the regular contribution... all the other information is the same as compound interest
every 6 months she is depositing, that means without considering interest itself, she should get : 525*2*11 money, your 1669 is very less
^^
So, M = 525 r = 5.4 n = 2 Right?
oops I gave future value when you want the present value... so you need to take the future value answer... and divide it by (1 +r)^n to find out how much you would need to invest now to get the same amount in 11 years
the present value formula is \[PV = M \times \frac{(1 + r)^n -1}{r(1 + r)^n}\]
so if you calculate the future value of the annuity it will be $30902.90 so what amount do you need to invest now... for the same return uses the compound interest fromula \[30902.90 = P( 1 + 0.054)^{22}\] just make P the subject
well its a bit to much.... that will depend on then the $525 deposits are made.... at the beginning or end of each period....
when we're not explicitly told, we can assume its an ordinary annuity
I am so lost...
I tried both of your formulas and I still get the wrong answers
...
I'll just guess. Thanks anyways.
its the last answer
No its not
well there you go... I just worked it out on a spread sheet and got the last answer...
This tells me otherwise though http://www.wolframalpha.com/input/?i=525*%28%281+%2B+0.054%2F2%29%5E%282+*+11%29-1%29%2F%280.054%2F2%29++%3D+x%281+%2B+0.054%2F2%29%5E%282*11%29
ok... there in lies the problem.... the interest rate was 5.4% per annum and not 5.4% per half year.... now it makes more sense....
So, the link I sent you was correct?
which is $8623.98
I'll take that as a yes lol
so find the future value using the formula \[FV = 525 \times \frac{(1 + 0.027)^{22} -1}{0.027}\] which is $15497.40 so now use the compound interest formula with the futrue value \[15497.4 = P \times (1 + 0.027)^{22}\] solve for P and you get answer A
Just checked and it was correct. (: Thanks
amazing how omitting p.a. changes the question
Indeed lol
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