Question

Need help with a worded question (im not very good at this) if you help will give Medal + Fan (:

Answer 1

@kaos_gabz

Answer 2

@Chris911

Answer 3

lol i tagged u and u tagged someone its like playing tag :P

Answer 4

Create a quadratic equation in standard form that can be factored.
start with it in factored form then multiply out
for example start with
\[(x-3)(x-2)\] and multiply to get
\[x^2-5x+6\] then you know it can be factored

Answer 5

dang it he beat me

Answer 6

Write your equation in factored form. Use complete sentences to explain the benefits of writing your equation in factored form.
since you started it in factored form, now you know it factors as
\[(x-3)(x-2)\]

Answer 7

its okay @Chris911 (: and thanks @satellite73

Answer 8

you can always count on chris !

Answer 9

u can lol

Answer 10

oh no chris can u help me? satellite logged off lol

Answer 11

In vertex form, a quadratic function is written as y = a(x-h)2 + k

Answer 12

^refer to http://www.mathopenref.com/quadvertexexplorer.html

Answer 13

okay sorry back was opening the website

Answer 14

hmm that last one is hard to explain but refer to http://jwilson.coe.uga.edu/EMT668/EMAT6680.Folders/Barron/unit/Lesson%206/6.html

Answer 15

okay i got this but im like positive its probably wrong but here it is: y=3/5x^2-0.3x+9/10

Answer 16

this is an excellent example as a graph quadratic funtion

Answer 17

Thank youuuu (:

Answer 18

now i just need to make my own graph ^.^ i like graphs

Answer 19

u my official fan ;) wink wink lool

Answer 20

hehe (: wait so was my vertex form right?

Answer 21

yes ;)

Answer 22

if not refer to a mod or get back with me and i will help u :)

Answer 23

-Write your equation in vertex form. Use complete sentences to explain the benefits of writing your equation in vertex form.

Answer 24

if you are going to have to write it in vertex form, i would start with a different example
i would start with
\[(x-2)(x-4)=x^2-6x+8\] which is factored on the left and in standard form on the right
then the vertex form is easy to find
since half of \(-6\) is \(-3\) it is
\[(x-3)^2+k\] and we can find \(k\) by replacing \(x\) by \(3\) in the original equation and get
\[k=3^2-6\times 3+8=9-18+8=-9+8=-1\] so vertex form is
\[y=(x-3)^2-1\]

Answer 25

Explain how all three forms can be used together to help you graph a quadratic function. Graph your function and label the y-intercept, the x-intercepts, and the vertex.
\[y=(x-2)(x-4)\] is good for finding the zeros, where the graph crosses the \(x\) axis, they are \(2\) and \(4\)

Answer 26

\[y=(x-3)^2-1\] is good for finding the vertex, it is \((3,-1)\)

Answer 27

and
\[y=x^2-6x+8\] looks pretty, it also finds the \(y\) intercept, it is \((0,8)\)

Answer 28

as usual i leave the complete sentences up to you

Answer 29

thank you both! (: