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Mathematics 8 Online
OpenStudy (anonymous):

correct my answer please?

OpenStudy (anonymous):

g'(f(x))*f'(x) = g'(f(4)*f'(4)

OpenStudy (anonymous):

f(4) = 8

OpenStudy (anonymous):

so g'(8)*f'(8)?

OpenStudy (anonymous):

so x = 16 and the slope is -1

OpenStudy (anonymous):

so is u'(4) = -1?

OpenStudy (phi):

to do this problem you need g(x) and f(x) g(x)= -x + 16 f(x) = 2x for 0≤x<8 g'(x) = -1 f'(x) = 2 g'(8)*f'(4) = -1*2 = -2 notice that because g' and f' are constant, the x values are irrelevant for this problem. for u(12) we must use a different function for f(x)

OpenStudy (anonymous):

okay so then u'(12) = 1 correct?

OpenStudy (anonymous):

i mean -1 , sorry

OpenStudy (anonymous):

wait no it must be 2 !!

OpenStudy (anonymous):

i get it now :) ty guys!!!

OpenStudy (phi):

what are you using for f(x) when x>8 ? it should be f(x)= -2x + 32 notice f(8)= 16, and f(16) =0, as it should g(x) =-x + 16 as a check, we can form u(x)= g(f(x)) = -( -2x + 32)+16 = 2x -16 and u' = 2 (independent of x) using the chain rule, you should get the same answer.

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