Question

Separating the variables in the equation ye^-x dy/dx = x gives you what equation?

Answer 1

ydy = xe^xdx

Answer 2

@Loser66 ODE?

Answer 3

Oh yea, I think so.

Answer 4

hey, if it is ODE, this stuff is the easiest one. good luck, hehehe

Answer 5

Well.. go figure. I'm terrible at math and made the mistake of joining AP Calc. Lol :(

Answer 6

hahaha. the same with me, I sit on the wrong class so that I am miserable now.

Answer 7

can you help me with another problem? It's similar to this one but it just goes right through my head. -_- I'll make another post if you want me to.

Answer 8

post

Answer 9

not sure I can help or not,

Answer 10

Want me to make a new post?

Answer 11

here is ok, as long as I can handle, no need to have a new post. to me, medal is nothing

Answer 12

Ok one sec, let me type out the equation from my textbook.

Answer 13

Which of the following is not a differential equation?

a. d^2y/dt^2 = t^2 + (y/4)
b. 4 + y = 2x + dx/dy
c. (x-x^3)dx = 4 - y^2
d. y' = 0
e. t^2 = s + (ds/dt)^2

Answer 14

a,c e

Answer 15

I think there is only one possible answer.

Answer 16

if so, take off a, and c, just pick e

Answer 17

Ok, thank you :D

Answer 18

hehehe

Answer 19

One more question, does dy/dx = dy(x)/dx ? Every time I put dy/dx into wolfram, it keeps showing it as dy(x)/dx.

Answer 20

I don't get the question. when I have to put dy/dx into worlfram, I put y'

Answer 21

and of course, y' w.r.t.x

Answer 22

Ah, I guess I'll try it that way then. I didn't want to screw up or misplace the variables because sometimes wolfram doesn't understand what I put in at all -_-