Question

limit approaches infinity (3/x^2 - 2/x) / (2/x^2 + 7/x)

I feel like the limit doesn't exist.
Can someone help1

Answer 1

Yeah your right the limit doesn't exist.

Answer 2

The limit as x approaches infinity exists.

Answer 3

I go up till lim x--> infinity 3 - 2x / 2 + 7x

Answer 4

Correct. Factor x out of numerator and denominator. They will cancel out. Then try x->infinity.

Answer 5

\[\frac{ 3-2x }{ 2+7x } = \frac{ x(3/x-2) }{ x(2/x+7) } = \frac{ 3/x-2 }{ 2/x+7}\]

Answer 6

When x-> infinity, 3/x -> 0 and 2/x -> 0 above.

Answer 7

thank you very much :)

Answer 8

You are welcome.