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Mathematics 22 Online
OpenStudy (anonymous):

Well I had helped quite a few students here earlier and now I wonder if some one is here to help me with this A video game producer is using the quadratic function f(x) = 4 – x2 to model the path of an arrow shot by a game player. The path of the arrow is shown in the graph below. The point (2, 3) represents the top of the castle wall. If the player moves so that the arrow will clear the wall at the maximum height, what is the new function that the game producer would need to use? Use complete sentences and explain your work.

OpenStudy (anonymous):

OpenStudy (fibonaccichick666):

alright, so, given a point and the "slope" could you find the eq?

OpenStudy (fibonaccichick666):

@ganibl

OpenStudy (anonymous):

Yes @FibonacciChick666

OpenStudy (fibonaccichick666):

so first, at what x value is the ball at it's highest point?

OpenStudy (anonymous):

From the graph I believe it is 2

OpenStudy (fibonaccichick666):

not quite, so the y value represents the height, where does the function have a max?

OpenStudy (anonymous):

at y= 4 function has maximum value

OpenStudy (fibonaccichick666):

uhm not exactly but you have the right idea, when you reference max and mins you want to say it occurs at x= not y=

OpenStudy (anonymous):

oh ok

OpenStudy (fibonaccichick666):

so where is the max again?

OpenStudy (anonymous):

x = 4 is maximum then?

OpenStudy (anonymous):

@FibonacciChick666

OpenStudy (fibonaccichick666):

no, what is the x value when y=4? just look at the graph, what are the coordinates of the max?

OpenStudy (anonymous):

Ok I got it now at x = 0 it is maximum Hope this time I got it right :)

OpenStudy (fibonaccichick666):

you did, yay! so now we have the max, but we want to change it's location, so what x value do we want the max to occur at?

OpenStudy (anonymous):

I think it is at x = 2 which means we need to shift it two units to the right this is what I understood please guide me if I am wrong

OpenStudy (fibonaccichick666):

yep that is the idea so what will our point for the new function be?

OpenStudy (anonymous):

(2, 4) ?

OpenStudy (fibonaccichick666):

good, so now we need to find the slope of our fn. Can you tell me the derivative of f(x)?

OpenStudy (anonymous):

I believe it is -2x but we do not have derivatives discussed so far

OpenStudy (fibonaccichick666):

oh,that sucks.... it is -2x so I mean using that you can find the answer, but let me think of another way to arrive at the same

OpenStudy (fibonaccichick666):

alright a bit more round about but I think we get the same

OpenStudy (fibonaccichick666):

so, we want to translate the graph two units to the right correct?

OpenStudy (anonymous):

Yes Exactly that is what I figured out

OpenStudy (anonymous):

I am thinking on translating equations method will help any idea on that?

OpenStudy (fibonaccichick666):

so we want to increase the x values by 2 right?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

(x + 2)^2 - 4?

OpenStudy (anonymous):

x^2 + 4x + 4 - 4 x^2 + 4x ? Ahh somewhere I might be wrong

OpenStudy (fibonaccichick666):

look at the original

OpenStudy (fibonaccichick666):

but that is my theory

OpenStudy (anonymous):

Oops sorry I got it right now 4 - (x + 2)^2

OpenStudy (fibonaccichick666):

alright, so let's see if that works

OpenStudy (fibonaccichick666):

check it using the derivative and the point would be my suggestion or graph it

OpenStudy (fibonaccichick666):

graphing is eqasier

OpenStudy (anonymous):

Ok Thanks much for your help @FibonacciChick666

OpenStudy (fibonaccichick666):

so it doesn't look quite right when I graph it

OpenStudy (fibonaccichick666):

it actually went to the left, so any ideas on how to fix it?

OpenStudy (anonymous):

So it should be 4 - (x - 2)^2 4 - x^2 + 4x - 4 x^2 - 4x ?

OpenStudy (fibonaccichick666):

yep

OpenStudy (anonymous):

So is that right?

OpenStudy (fibonaccichick666):

yup

OpenStudy (anonymous):

Thanks @FibonacciChick666 Your help is greatly appreciated

OpenStudy (fibonaccichick666):

np

OpenStudy (fibonaccichick666):

:)

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