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Mathematics 7 Online
OpenStudy (doc.brown):

What's the opposite of "distributes"?

OpenStudy (doc.brown):

\[a(b+c)=ab+ac\]

OpenStudy (anonymous):

division... Cause when you distribute it is multiplication. so technically i think it would be: b/a+c/a..

OpenStudy (doc.brown):

I mean if I have \(a(b+c)\) I say "\(a\) is distributed" Would I say in \(ab+ac\), that \(a\) is divided?

OpenStudy (anonymous):

no.... it is multiplied. Cause lets give them values... a=2 b=4 and c=3 2(4+3)= 2*4+2*3....

OpenStudy (bibby):

If you call a the common factor, it'd be clear.

OpenStudy (doc.brown):

...but it's the "distributive law".

OpenStudy (anonymous):

and to distribute just means multiply.

OpenStudy (bibby):

a IS divided though\[\huge \frac{ ab+bc }{ a } = \frac{ ab }{ a }+ \frac{ ac }{ a } = b+c\]

OpenStudy (anonymous):

@bibby I am really confused as to why you did that....

OpenStudy (bibby):

because factoring out an a means dividing the term by a

OpenStudy (anonymous):

yeah, but we aren't factoring out in this case.... we are distributing....

OpenStudy (doc.brown):

I see my problem. The distributive property goes both ways. I distribute my undivided thanks.

OpenStudy (bibby):

I'm just showing how it goes both ways.

OpenStudy (anonymous):

okay... I gotcha. Makes sense.

OpenStudy (bibby):

I meant to do this, a(ab+ac) ------ a

OpenStudy (doc.brown):

I got your meaning, thanks @bibby

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