Question

I don't like these things:

Identify the equation for the hyperbola with vertices at (3, 0) and (-3, 0), and an asymptote at y = 7/3x.

7x^2 - 49y^2 = 441
7x^2 - 9y^2 = 441
49x^2 - 9y^2 = 441
49x^2 + 9y^2 = 441

Answer 1

Here are my notes on hyperbolas
Hyperbola\(\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1\)
Vertices \((\pm a,0)\)
Asymptotes \(y=\dfrac{\pm b}{a}x\)
Eccentricity \(e=\dfrac{\sqrt{a^2+b^2}}{a}\)
Length Latus Rectum = \(\dfrac{2b^2}{a}\)
Focal Length \(f=\sqrt{a^2+b^2}\)