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CaC2(s) + H2O(l) > Ca(OH)2 (s)+ C2H2(g) What is the maximum number of grams of C2H2 that can be produced if 8 grams of CaC2 and 8g of H20 are allowed to react? Please explain step by step
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First calculate amount of substance n Of reactants. It seems that there should be 2 in front of water. You have to take it account. Also, if amount of CaC2 is less than half of H2O It is limiting reactant, otherwise it is H2O. Then you find out number of moles of C2H2 and calculate mass.
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