What comes next in the sequence: 1, 3, 11, 43, ____? 161 171 181 191
any specific formula to find out sequence?
\[1\color{red}{+2},3\color{red}{+8},11\color{red}{+32},43\]see a pattern?
Hint: \[2^1 = 2, 2^3 = 8, 2^5 = 32, 2^7 = 128\]
hmm
but correct ans is 171
The powers of 2 in my list correspond to the red numbers in @doc.brown 's list
That's right, the correct answer is 171. Follow the pattern in both of our lists to get 171.
ok ok
You know you are increasing the powers of 2 by odds because of the established pattern from 1-> 3 -> 5
OP left
I always try increasing the numbers in an addy kind of way, if that doesn't work, try increasing the numbers in a timesy kind of way.\[1\color{blue}{\times3},3\color{blue}{\times3\frac{2}{3}},11\color{blue}{\times3\frac{909}{1000}},43\]Which is even less helpful in this case, but I wanted to show you.
\[\text{Table}\left[\frac{1}{6} \left(2^{2 n}+2\right),\{n,8\}\right]=\{1,3,11,43,171,683,2731,10923\} \]
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