The diagram shows an electron, with charge e, mass m, and velocity v, entering a uniform electric field of strength E. http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20%289702%29/9702_s09_qp_1.pdf Scroll down to Question No.) 29 The direction of the field and the electron’s motion are both horizontal and to the right. Which expression gives the distance x hrough which the electron travels before it stops momentarily? the options and diagram is given in the link above the answer is D but I want to know why is it so?
Well.. thats simple 1D kinematics whats the acceleration (retardation in this case) experienced by the electron?
there is no number given
tell me the expression!
uhm that's the thing, I don't why they are using kinetic energy in this
forget about kinetic energy.. :P just answer my question.. what is the acceleration ? (in terms of E, e, and m)
I looked through my book: the only thing that is coming in my mind is E=F/Q or V/d I don't know how you relate that with F=ma though :/
you already wrote two equations E = F/q and F = ma using these equations can't u relate them? :D
*hint eliminate F * shhhhshhhhhhh..
uhm.....F= E/Q aaand F= Ma soooo......
sooooooo... ?
wait.. F is NOT E/q E = F/q
wait I'm looking for distance right?
no u are looking for acceleration.. !!! plz focus here.. ll walking you through this.. but i can't help you if you don't follow me step by step :O
I'm trying >___<
so elimate F from the two equations here E = F/Q => F = EQ and F = ma so what is a ???
so acceleration is Force/ Mass right?
If that's what we are looking for right?
i want a in terms of (E, m and Q).. using those two equations..
so If I make F as the subject in the E= F/Q formula the F is E x Q over mass?
or may be I just screwed it up
T_T
WHAT?!.. JUST EQUATE THE TWO EQUATIONS.. :O .. u are telling me you can't do that?!? :O
F= ma F = EQ THEREFORE ma = EQ NOW WHAT IS 'a' ????
if you don't answer this right.. ll kil you!
EQ/m!!!!
Okay! Okay!
=_=
THERE.. was that so hard? :P now Q = e therefore a = Ee/m now the electron is going to the right.. but which direction does it experience the force.. hence which direction is the acceleration? left or right?
it's going along in the direction of the electric field so it's right?
uh-oh don't tell me I got it wrong agian??? o_O
if that is the case.. then it should speed up .. and keep going.. why would it ever stop and turn back?
so there is a force opposing it to make it stop
yes.. so acceleration is directed towards ...... ?
left
ok so we can call it negative now u know initial velocity = v u know acceleration = -eE/m u know final velocity = 0 (cause it stops) can u calculate the distance? x ?
do we use one of the equation of motion like this one? v^2 = u^2 + 2as? (where u is the initial velocity and s is the displacement)
yea.. precisely!
*applauds* :P
=_='''' thank you miss genius
o.O .. u now made the biggest mistake of your life in your final reply i dunno who you are, but m gonna find you , m gonna hunt you.. and i WILL KILL YOU!
what?? lol hahaha I complemented you >xD
i meant the 'miss' part ITS MR. now did you get the answer?
ohhh Ooops sorry sir ^.^'
uhm......all my friends and me are dumb in maths (hence physics) so I didn't get it when you said "equate two equations" it's a utter shame (I know lol) but who do you equate two equations?
*what do you mean by saying equate
meaning eliminating a variable liek if x = 2y and y = 3z then i can elimnate y x = 2(3z) => x = 6y
btw.. did you get the answer? how many times should i ask :(
I got it don't worry, don't worry :D
x = 6z * sorry :D
now i wanted to tell you how to do it using energy.. u wanna know? or you are fine with acceleration method? :P
Oooohh I see
oh I don't mind please go ahead :)
well.. u use the concept of conservation of energy.. |dw:1396706815519:dw| what i have drawn is equipotential line when the electron moves down the field ( its moving towards the lower potential region) since E = V/d V = Ed and since i already took intiially as V = 0, the line to the right x distance away is at a potential -Ex so far so good?
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