How long does it take your money to double at 8% interest?
A close approximation is the "rule of 72" which is that the product of the interest rate and the time needed to double is 72 so 72 = 8 x and x = 9. Else, (1+0.08)^x = 2 take log of both sides x ln(1.08) = ln 2 x = ln(2)/ln(1.08) = 9.006
they want me to use the formula... \[A=Pe^{rt}\]
Doubling means that A'/A = 2 A'/A = exp(rt')/exp(rt) = 2 ln 2 = rt' - rt = r (t'-t) set t = 0 to start ln 2 = r t' = 0.08 t' t' = ln 2 / 0.08 = 8.66 The difference (9 vs. 8.66) is because the exp(rt) equation assumes continuous compounding and the (1+r)^t assumes compounding only at unit intervals of t, like years.
Glad to have been of help.
okay why does A= exponent rt?
how would we plug into the formula... meaning what does each variable represent in this case in the formula I gave you.
The amount = principal times growth factor let N be the number of dollars in the account dN/dt = N r growth equation for rate r dN/N = r dt then integrate from t=0 to t ln N - ln No = r t express as exponential N = No exp(rt) A = P exp(rt) in financial notation
Okay , I don't think I 'll ever fully understand how to set this up, but thanks for the help.
A is the amount you get after some time t ... A = Pe^rt; well P is doubled when A = 2P 2P = Pe^rt ... divide and log out
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