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Geometry 9 Online
OpenStudy (anonymous):

Do I have to use the Pyth. Theorem on this triangle?

OpenStudy (anonymous):

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hartnn (hartnn):

52 is the angle, right ? then no, no pythagoras....this belongs to trigonometry, right ?

OpenStudy (anonymous):

yes, 52 is the angle, and this is geometry, not trig.

mathslover (mathslover):

Well, if you want to make it more complicated, then we can use Pythagoras theorem but I will suggest to use trigonometry here.

mathslover (mathslover):

Remember : "soh cah toa" \(\sin = \cfrac{\sf{Opposite}}{\sf{Hypotenuse}} \) \(\cos = \cfrac{\sf{adjacent}}{\sf{Hypotenuse}}\) \(\tan = \cfrac{\sf{Opposite}}{\sf{Adjacent}}\)

OpenStudy (anonymous):

pythagoras +trgonometry

OpenStudy (anonymous):

On this triangle, which one is the Hypotenuse?

mathslover (mathslover):

The longest side is Hypotenuse.

OpenStudy (anonymous):

so in this case, x would be the hyp.?

mathslover (mathslover):

or the side opposite to the Right Angle

OpenStudy (anonymous):

okay, so in this case, it wouldn't be x, it would be the unnamed side

hartnn (hartnn):

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