Do I have to use the Pyth. Theorem on this triangle?
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52 is the angle, right ? then no, no pythagoras....this belongs to trigonometry, right ?
yes, 52 is the angle, and this is geometry, not trig.
Well, if you want to make it more complicated, then we can use Pythagoras theorem but I will suggest to use trigonometry here.
Remember : "soh cah toa" \(\sin = \cfrac{\sf{Opposite}}{\sf{Hypotenuse}} \) \(\cos = \cfrac{\sf{adjacent}}{\sf{Hypotenuse}}\) \(\tan = \cfrac{\sf{Opposite}}{\sf{Adjacent}}\)
pythagoras +trgonometry
On this triangle, which one is the Hypotenuse?
The longest side is Hypotenuse.
so in this case, x would be the hyp.?
or the side opposite to the Right Angle
okay, so in this case, it wouldn't be x, it would be the unnamed side
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