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f(x)= 4e^(xcos(x)) deravative? please
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knpow about chain rule ?
yeah but wouldn't ex be the same
\(\Large (4e^{x \cos x})' = 4e^{x\cos x} \times (x\cos x )'\)
what would the derivative of the (xcosx )be? please tell me!
by chain rule
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know product rule ?
\((fg)' = f'g+fg'\)
here f= x g = cos x
ohh right haha, thanku
sorry I mean product rule
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\[der(x)=4e ^{xcosx}[x(sinx)+cosx]\]
[cosx - xsinx]
yes :)
THankyou!! guys
welcome girl ^_^
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most welcome
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