suppose that f(4)=3 and f ' (4)=-5. Find g ' (4) where g(x)=√x f(x).
find dg/dx then put in those values
but how find dg/dx ?
for this =√x f(x).
yes
okey how ?!
do u know the product rule?
I know that but what mean this f(x) in √x f(x). ?
its just a function ... the value for it is defined in the given statement so just derive g
the function g, is composed of the product of the function sqrt(x), and the function f(x) apply the product rule ....
=1/2(x)^-1/2 . f(x) + (x)^1/2 . ?
what is the derivative of f(x) ??
=1 ?
BRB I come back >
no .. would you agree that the derivative of g(x) ... is g'(x) ?? if so, the what is the derivative of f(x) notate out to be?
y derives to y' g derives to g' h derives to h' f derives to ____ ???
f'
and its a good thing that they define f(4) and also f'(4) for us doesnt it
so =1/2(x)^-1/2 . f(4) + (x)^1/2 . f'(4) ?
close .. when x=4, then you might want to evaluate it all for x=4
g' (x)=1/2(x)^-1/2 . f(x) + (x)^1/2 . f'(x) g' (4)=1/2(4)^-1/2 . f(4) + (4)^1/2 . f'(4)
like that ? =1/2(4)^-1/2 . f(4) + (4)^1/2 . f'(4) ?
exactly
thanks a lot :)
yep ;)
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