Question

please help ,
limit n tends to infinity log n/n^0.1 =??
^=to the power

Answer 1

\[\lim_{n \rightarrow \infty } (\log n)/n ^{0.1}\]

Answer 2

try l'hopitals rule

Answer 3

but isn't it for log n/n
here the power of n=0.1
how cn we apply L'hospital rule here ?

Answer 4

l'hopitals rule applies for function which are indeterminate like 0/0 amd inf / inf
yea you are probably right - i studied limits last year in my maths course and i'm afraid they are not my strong point.

Answer 5

ohh !!

Answer 6

sorry

Answer 7

np, thank u :)

Answer 8

i know that limit of log n as n approaches infinity is infinity

Answer 9

then i think we cn apply L'hospital rule
as it is an indeterminatistic form !

Answer 10

ok lets try it

differentiating

= 1/n
------
0.1n^-0.9


= 1
-------
o.1n * n ^-0.9


= 1 / 0.1 n^0.1

= 0 as n approaches infinity

Answer 11

I checked it out on wolframalpha - thats the right answer

Answer 12

thank u :)