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OpenStudy (helder_edwin):
u need to factor the 150
\[\large 3\sqrt{150b^8}=3(2\cdot3\cdot5^2b^8)^{1/2}=
3(2\cdot 3)^{1/2}(5^2)^{1/2}(b^8)^{1/2}= \]
\[\large =3\cdot5\cdot b^4\sqrt{6}=15b^4\sqrt{6} \]
OpenStudy (danielbarriosr1):
I didnt get anything
OpenStudy (danielbarriosr1):
@mathmale
OpenStudy (danielbarriosr1):
Someone please
OpenStudy (yanasidlinskiy):
Does @helder_edwin work not help you?? What's the problem?? Do you not understand it or you don't know how to figure it out??
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OpenStudy (danielbarriosr1):
i dont understand it
OpenStudy (helder_edwin):
i told u that u need to factor 150 so
\[\large 150=2\cdot3\cdot5^2 \]
OpenStudy (danielbarriosr1):
Yes
OpenStudy (helder_edwin):
next i wrote the square root as an exponent
\[\large \sqrt{A}=a^{1/2} \]
then the property of exponents
\[\large (AB)^n=A^nB^n \]
and finally
\[\large (A^n)^m=A^{n\times m} \]
u should be familiar with all these.
OpenStudy (helder_edwin):
sorry a typo:
\[\large \sqrt{A}=A^{1/2} \]
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OpenStudy (danielbarriosr1):
Can it be like this:
\[3(\sqrt{15b^7}*\sqrt{10b})\]
OpenStudy (danielbarriosr1):
?
OpenStudy (helder_edwin):
yes it COULD be like that. but what u wrote is completely useless for the purpose of the exercise.